Base | Representation |
---|---|
bin | 1001100100011111010001… |
… | …10100101101010011111101 |
3 | 2202111212200210221222021121 |
4 | 10302033220310231103331 |
5 | 10224300024413224201 |
6 | 112431530022430541 |
7 | 4301306334160126 |
oct | 462175064552375 |
9 | 82455623858247 |
10 | 21044950914301 |
11 | 6784128172186 |
12 | 243a79b592451 |
13 | b986b8265502 |
14 | 52a81c5d704d |
15 | 267662a919a1 |
hex | 1323e8d2d4fd |
21044950914301 has 2 divisors, whose sum is σ = 21044950914302. Its totient is φ = 21044950914300.
The previous prime is 21044950914193. The next prime is 21044950914313. The reversal of 21044950914301 is 10341905944012.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20391320705625 + 653630208676 = 4515675^2 + 808474^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21044950914301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21044950914341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10522475457150 + 10522475457151.
It is an arithmetic number, because the mean of its divisors is an integer number (10522475457151).
Almost surely, 221044950914301 is an apocalyptic number.
It is an amenable number.
21044950914301 is a deficient number, since it is larger than the sum of its proper divisors (1).
21044950914301 is an equidigital number, since it uses as much as digits as its factorization.
21044950914301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 155520, while the sum is 43.
The spelling of 21044950914301 in words is "twenty-one trillion, forty-four billion, nine hundred fifty million, nine hundred fourteen thousand, three hundred one".
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