21050130123131 has 2 divisors, whose sum is σ = 21050130123132. Its totient is φ = 21050130123130.

The previous prime is 21050130123107. The next prime is 21050130123133. The reversal of 21050130123131 is 13132103105012.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21050130123131 - 2⁴² = 16652083612027 is a prime.

It is a super-2 number, since 2×21050130123131² (a number of 27 digits) contains 22 as substring.

Together with 21050130123133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 21050130123097 and 21050130123106.

It is not a weakly prime, because it can be changed into another prime (21050130123133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10525065061565 + 10525065061566.

It is an arithmetic number, because the mean of its divisors is an integer number (10525065061566).

Almost surely, 2^{21050130123131} is an apocalyptic number.

21050130123131 is a deficient number, since it is larger than the sum of its proper divisors (1).

21050130123131 is an equidigital number, since it uses as much as digits as its factorization.

21050130123131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 21050130123131 its reverse (13132103105012), we get a palindrome (34182233228143).

The spelling of 21050130123131 in words is "twenty-one trillion, fifty billion, one hundred thirty million, one hundred twenty-three thousand, one hundred thirty-one".