Base | Representation |
---|---|
bin | 1001100100101000111011… |
… | …00001110100100110000110 |
3 | 2202112101001202120001011021 |
4 | 10302110131201310212012 |
5 | 10224341131302420032 |
6 | 112434143555101354 |
7 | 4301551563546301 |
oct | 462243541644606 |
9 | 82471052501137 |
10 | 21050130123142 |
11 | 678634575146a |
12 | 243b7a5ba185a |
13 | b9903227bb23 |
14 | 52ab903c7b38 |
15 | 2678675e7097 |
hex | 13251d874986 |
21050130123142 has 4 divisors (see below), whose sum is σ = 31575195184716. Its totient is φ = 10525065061570.
The previous prime is 21050130123137. The next prime is 21050130123181. The reversal of 21050130123142 is 24132103105012.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5262532530784 + ... + 5262532530787.
It is an arithmetic number, because the mean of its divisors is an integer number (7893798796179).
Almost surely, 221050130123142 is an apocalyptic number.
21050130123142 is a deficient number, since it is larger than the sum of its proper divisors (10525065061574).
21050130123142 is a wasteful number, since it uses less digits than its factorization.
21050130123142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10525065061573.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 21050130123142 its reverse (24132103105012), we get a palindrome (45182233228154).
The spelling of 21050130123142 in words is "twenty-one trillion, fifty billion, one hundred thirty million, one hundred twenty-three thousand, one hundred forty-two".
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