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211000022113 is a prime number
BaseRepresentation
bin1100010010000010010…
…1001101010001100001
3202011121221202201001211
43010200211031101201
511424112001201423
6240533154430121
721146530411216
oct3044045152141
9664557681054
10211000022113
1181537014671
1234a87592341
1316b882538ba
14a2d8d99b0d
15574e01a10d
hex312094d461

211000022113 has 2 divisors, whose sum is σ = 211000022114. Its totient is φ = 211000022112.

The previous prime is 211000022081. The next prime is 211000022117. The reversal of 211000022113 is 311220000112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 209038240849 + 1961781264 = 457207^2 + 44292^2 .

It is a cyclic number.

It is not a de Polignac number, because 211000022113 - 25 = 211000022081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211000022093 and 211000022102.

It is not a weakly prime, because it can be changed into another prime (211000022117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105500011056 + 105500011057.

It is an arithmetic number, because the mean of its divisors is an integer number (105500011057).

Almost surely, 2211000022113 is an apocalyptic number.

It is an amenable number.

211000022113 is a deficient number, since it is larger than the sum of its proper divisors (1).

211000022113 is an equidigital number, since it uses as much as digits as its factorization.

211000022113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 211000022113 its reverse (311220000112), we get a palindrome (522220022225).

The spelling of 211000022113 in words is "two hundred eleven billion, twenty-two thousand, one hundred thirteen".