Base | Representation |
---|---|
bin | 1100010010000010011… |
… | …0010100010100001111 |
3 | 202011121222022111020020 |
4 | 3010200212110110033 |
5 | 11424112040004403 |
6 | 240533204553223 |
7 | 21146533032456 |
oct | 3044046242417 |
9 | 664558274206 |
10 | 211000313103 |
11 | 815371a3258 |
12 | 34a876b2813 |
13 | 16b88326198 |
14 | a2d9033b9d |
15 | 574e076453 |
hex | 312099450f |
211000313103 has 64 divisors (see below), whose sum is σ = 309688811520. Its totient is φ = 127290009600.
The previous prime is 211000313093. The next prime is 211000313113. The reversal of 211000313103 is 301313000112.
It is an interprime number because it is at equal distance from previous prime (211000313093) and next prime (211000313113).
It is not a de Polignac number, because 211000313103 - 221 = 210998215951 is a prime.
It is a super-2 number, since 2×2110003131032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211000313113) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 44672700 + ... + 44677422.
It is an arithmetic number, because the mean of its divisors is an integer number (4838887680).
Almost surely, 2211000313103 is an apocalyptic number.
211000313103 is a deficient number, since it is larger than the sum of its proper divisors (98688498417).
211000313103 is a wasteful number, since it uses less digits than its factorization.
211000313103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5100.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 211000313103 its reverse (301313000112), we get a palindrome (512313313215).
The spelling of 211000313103 in words is "two hundred eleven billion, three hundred thirteen thousand, one hundred three".
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