Base | Representation |
---|---|
bin | 101111111110011101100001… |
… | …110111100110010010000111 |
3 | 1000200002110011122201101102001 |
4 | 233332131201313212102013 |
5 | 210124013011040042041 |
6 | 2024432143000330131 |
7 | 62305166045230222 |
oct | 5776354167462207 |
9 | 1020073148641361 |
10 | 211000500315271 |
11 | 6125a89a724557 |
12 | 1b7b9388773947 |
13 | 9097353248674 |
14 | 3a1669b7d45b9 |
15 | 195d919625131 |
hex | bfe761de6487 |
211000500315271 has 2 divisors, whose sum is σ = 211000500315272. Its totient is φ = 211000500315270.
The previous prime is 211000500315223. The next prime is 211000500315373. The reversal of 211000500315271 is 172513005000112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211000500315271 - 233 = 210991910380679 is a prime.
It is a super-2 number, since 2×2110005003152712 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211000500315221) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105500250157635 + 105500250157636.
It is an arithmetic number, because the mean of its divisors is an integer number (105500250157636).
Almost surely, 2211000500315271 is an apocalyptic number.
211000500315271 is a deficient number, since it is larger than the sum of its proper divisors (1).
211000500315271 is an equidigital number, since it uses as much as digits as its factorization.
211000500315271 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2100, while the sum is 28.
Adding to 211000500315271 its reverse (172513005000112), we get a palindrome (383513505315383).
The spelling of 211000500315271 in words is "two hundred eleven trillion, five hundred million, three hundred fifteen thousand, two hundred seventy-one".
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