Base | Representation |
---|---|
bin | 1100010010000010100… |
… | …1011001010101101111 |
3 | 202011122000211111020102 |
4 | 3010200221121111233 |
5 | 11424112241320421 |
6 | 240533234141315 |
7 | 21146542633325 |
oct | 3044051312557 |
9 | 664560744212 |
10 | 211001120111 |
11 | 815376a4601 |
12 | 34a87a2183b |
13 | 16b885495c2 |
14 | a2d91a3d15 |
15 | 574e18560b |
hex | 3120a5956f |
211001120111 has 2 divisors, whose sum is σ = 211001120112. Its totient is φ = 211001120110.
The previous prime is 211001120093. The next prime is 211001120117. The reversal of 211001120111 is 111021100112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211001120111 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 211001120092 and 211001120101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211001120117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105500560055 + 105500560056.
It is an arithmetic number, because the mean of its divisors is an integer number (105500560056).
Almost surely, 2211001120111 is an apocalyptic number.
211001120111 is a deficient number, since it is larger than the sum of its proper divisors (1).
211001120111 is an equidigital number, since it uses as much as digits as its factorization.
211001120111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4, while the sum is 11.
Adding to 211001120111 its reverse (111021100112), we get a palindrome (322022220223).
The spelling of 211001120111 in words is "two hundred eleven billion, one million, one hundred twenty thousand, one hundred eleven".
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