Base | Representation |
---|---|
bin | 11110101101000111000… |
… | …111001010010111010101 |
3 | 21110201100001122122120222 |
4 | 132231013013022113111 |
5 | 234032311113032013 |
6 | 4253155234204125 |
7 | 305305212043463 |
oct | 36550707122725 |
9 | 7421301578528 |
10 | 2110022002133 |
11 | 743945459481 |
12 | 2a0b2a123645 |
13 | 123c88495a96 |
14 | 741a895d833 |
15 | 39d46ebe508 |
hex | 1eb471ca5d5 |
2110022002133 has 2 divisors, whose sum is σ = 2110022002134. Its totient is φ = 2110022002132.
The previous prime is 2110022002129. The next prime is 2110022002201. The reversal of 2110022002133 is 3312002200112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1868997954769 + 241024047364 = 1367113^2 + 490942^2 .
It is a cyclic number.
It is not a de Polignac number, because 2110022002133 - 22 = 2110022002129 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2110022002103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055011001066 + 1055011001067.
It is an arithmetic number, because the mean of its divisors is an integer number (1055011001067).
Almost surely, 22110022002133 is an apocalyptic number.
It is an amenable number.
2110022002133 is a deficient number, since it is larger than the sum of its proper divisors (1).
2110022002133 is an equidigital number, since it uses as much as digits as its factorization.
2110022002133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 2110022002133 its reverse (3312002200112), we get a palindrome (5422024202245).
The spelling of 2110022002133 in words is "two trillion, one hundred ten billion, twenty-two million, two thousand, one hundred thirty-three".
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