Base | Representation |
---|---|
bin | 11110101101000111001… |
… | …011110001110001000111 |
3 | 21110201100010221010100200 |
4 | 132231013023301301013 |
5 | 234032311420241403 |
6 | 4253155320141543 |
7 | 305305225243212 |
oct | 36550713616107 |
9 | 7421303833320 |
10 | 2110023212103 |
11 | 743946105554 |
12 | 2a0b2a6078b3 |
13 | 123c887ca741 |
14 | 741a8b96779 |
15 | 39d4715cca3 |
hex | 1eb472f1c47 |
2110023212103 has 48 divisors (see below), whose sum is σ = 3233164334400. Its totient is φ = 1323672860160.
The previous prime is 2110023212083. The next prime is 2110023212183. The reversal of 2110023212103 is 3012123200112.
It is not a de Polignac number, because 2110023212103 - 25 = 2110023212071 is a prime.
It is a super-2 number, since 2×21100232121032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2110023212183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 10245913 + ... + 10449821.
It is an arithmetic number, because the mean of its divisors is an integer number (67357590300).
Almost surely, 22110023212103 is an apocalyptic number.
2110023212103 is a deficient number, since it is larger than the sum of its proper divisors (1123141122297).
2110023212103 is a wasteful number, since it uses less digits than its factorization.
2110023212103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 204952 (or 204949 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 2110023212103 its reverse (3012123200112), we get a palindrome (5122146412215).
The spelling of 2110023212103 in words is "two trillion, one hundred ten billion, twenty-three million, two hundred twelve thousand, one hundred three".
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