Base | Representation |
---|---|
bin | 1001100110000110011001… |
… | …00111010011001101010011 |
3 | 2202201011121001000022011021 |
4 | 10303003030213103031103 |
5 | 10231201414411243212 |
6 | 112513203303300311 |
7 | 4305306256351246 |
oct | 463031447231523 |
9 | 82634531008137 |
10 | 21100312212307 |
11 | 67a5657183829 |
12 | 244946ba4a697 |
13 | ba099b974603 |
14 | 52d390d9725d |
15 | 268d02e59307 |
hex | 1330cc9d3353 |
21100312212307 has 2 divisors, whose sum is σ = 21100312212308. Its totient is φ = 21100312212306.
The previous prime is 21100312212253. The next prime is 21100312212347. The reversal of 21100312212307 is 70321221300112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21100312212307 - 215 = 21100312179539 is a prime.
It is not a weakly prime, because it can be changed into another prime (21100312212347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10550156106153 + 10550156106154.
It is an arithmetic number, because the mean of its divisors is an integer number (10550156106154).
Almost surely, 221100312212307 is an apocalyptic number.
21100312212307 is a deficient number, since it is larger than the sum of its proper divisors (1).
21100312212307 is an equidigital number, since it uses as much as digits as its factorization.
21100312212307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 21100312212307 its reverse (70321221300112), we get a palindrome (91421533512419).
The spelling of 21100312212307 in words is "twenty-one trillion, one hundred billion, three hundred twelve million, two hundred twelve thousand, three hundred seven".
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