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211004113 is a prime number
BaseRepresentation
bin11001001001110…
…10101011010001
3112201001010020011
430210322223101
5413004112423
632534314521
75141335225
oct1444725321
9481033204
10211004113
11a9119571
125a7b8a41
133493ac08
1420048785
15137ceb0d
hexc93aad1

211004113 has 2 divisors, whose sum is σ = 211004114. Its totient is φ = 211004112.

The previous prime is 211004099. The next prime is 211004141. The reversal of 211004113 is 311400112.

211004113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 210018064 + 986049 = 14492^2 + 993^2 .

It is a cyclic number.

It is not a de Polignac number, because 211004113 - 29 = 211003601 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211004093 and 211004102.

It is not a weakly prime, because it can be changed into another prime (211004173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105502056 + 105502057.

It is an arithmetic number, because the mean of its divisors is an integer number (105502057).

Almost surely, 2211004113 is an apocalyptic number.

It is an amenable number.

211004113 is a deficient number, since it is larger than the sum of its proper divisors (1).

211004113 is an equidigital number, since it uses as much as digits as its factorization.

211004113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 211004113 is about 14525.9806209426. The cubic root of 211004113 is about 595.3380495502.

Adding to 211004113 its reverse (311400112), we get a palindrome (522404225).

The spelling of 211004113 in words is "two hundred eleven million, four thousand, one hundred thirteen".