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211010121000121 is a prime number
BaseRepresentation
bin101111111110100110011111…
…010011100110010010111001
31000200010101000010201210222011
4233332212133103212102321
5210124142211434000441
62024440413353125521
762305656335551132
oct5776463723462271
91020111003653864
10211010121000121
1161263987311473
121b7bb2126b98a1
1390982274875b1
143a16d31418c89
15195dcce058581
hexbfe99f4e64b9

211010121000121 has 2 divisors, whose sum is σ = 211010121000122. Its totient is φ = 211010121000120.

The previous prime is 211010121000089. The next prime is 211010121000143. The reversal of 211010121000121 is 121000121010112.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 136800252314896 + 74209868685225 = 11696164^2 + 8614515^2 .

It is a cyclic number.

It is not a de Polignac number, because 211010121000121 - 25 = 211010121000089 is a prime.

It is not a weakly prime, because it can be changed into another prime (211010121007121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105505060500060 + 105505060500061.

It is an arithmetic number, because the mean of its divisors is an integer number (105505060500061).

Almost surely, 2211010121000121 is an apocalyptic number.

It is an amenable number.

211010121000121 is a deficient number, since it is larger than the sum of its proper divisors (1).

211010121000121 is an equidigital number, since it uses as much as digits as its factorization.

211010121000121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 211010121000121 its reverse (121000121010112), we get a palindrome (332010242010233).

Subtracting from 211010121000121 its reverse (121000121010112), we obtain a palindrome (90009999990009).

The spelling of 211010121000121 in words is "two hundred eleven trillion, ten billion, one hundred twenty-one million, one hundred twenty-one", and thus it is an aban number.