Base | Representation |
---|---|
bin | 1100010010000100111… |
… | …1001010010101010001 |
3 | 202011122201110110111011 |
4 | 3010201033022111101 |
5 | 11424122310120423 |
6 | 240534230250521 |
7 | 21150023035315 |
oct | 3044117122521 |
9 | 664581413434 |
10 | 211011020113 |
11 | 81542246623 |
12 | 34a8b1b6a41 |
13 | 16b8a6047aa |
14 | a2da61db45 |
15 | 574ee8db0d |
hex | 31213ca551 |
211011020113 has 2 divisors, whose sum is σ = 211011020114. Its totient is φ = 211011020112.
The previous prime is 211011020089. The next prime is 211011020147. The reversal of 211011020113 is 311020110112.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 125424347409 + 85586672704 = 354153^2 + 292552^2 .
It is a cyclic number.
It is not a de Polignac number, because 211011020113 - 217 = 211010889041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 211011020093 and 211011020102.
It is not a weakly prime, because it can be changed into another prime (211011020153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105505510056 + 105505510057.
It is an arithmetic number, because the mean of its divisors is an integer number (105505510057).
Almost surely, 2211011020113 is an apocalyptic number.
It is an amenable number.
211011020113 is a deficient number, since it is larger than the sum of its proper divisors (1).
211011020113 is an equidigital number, since it uses as much as digits as its factorization.
211011020113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 211011020113 its reverse (311020110112), we get a palindrome (522031130225).
The spelling of 211011020113 in words is "two hundred eleven billion, eleven million, twenty thousand, one hundred thirteen".
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