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21101200220131 is a prime number
BaseRepresentation
bin1001100110001000000011…
…00010110001111111100011
32202201020212220221202212221
410303010001202301333203
510231210224224021011
6112513431344331511
74305340261322323
oct463040142617743
982636786852787
1021101200220131
1167a5a72465199
122449679313b97
13ba0ab092c725
1452d436cb1283
15268d55db7971
hex1331018b1fe3

21101200220131 has 2 divisors, whose sum is σ = 21101200220132. Its totient is φ = 21101200220130.

The previous prime is 21101200220129. The next prime is 21101200220167. The reversal of 21101200220131 is 13102200210112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 21101200220131 - 21 = 21101200220129 is a prime.

It is a super-2 number, since 2×211012002201312 (a number of 27 digits) contains 22 as substring.

Together with 21101200220129, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (21101200224131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10550600110065 + 10550600110066.

It is an arithmetic number, because the mean of its divisors is an integer number (10550600110066).

Almost surely, 221101200220131 is an apocalyptic number.

21101200220131 is a deficient number, since it is larger than the sum of its proper divisors (1).

21101200220131 is an equidigital number, since it uses as much as digits as its factorization.

21101200220131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 21101200220131 its reverse (13102200210112), we get a palindrome (34203400430243).

The spelling of 21101200220131 in words is "twenty-one trillion, one hundred one billion, two hundred million, two hundred twenty thousand, one hundred thirty-one".