Base | Representation |
---|---|
bin | 1001100110001000000011… |
… | …00010110001111111100011 |
3 | 2202201020212220221202212221 |
4 | 10303010001202301333203 |
5 | 10231210224224021011 |
6 | 112513431344331511 |
7 | 4305340261322323 |
oct | 463040142617743 |
9 | 82636786852787 |
10 | 21101200220131 |
11 | 67a5a72465199 |
12 | 2449679313b97 |
13 | ba0ab092c725 |
14 | 52d436cb1283 |
15 | 268d55db7971 |
hex | 1331018b1fe3 |
21101200220131 has 2 divisors, whose sum is σ = 21101200220132. Its totient is φ = 21101200220130.
The previous prime is 21101200220129. The next prime is 21101200220167. The reversal of 21101200220131 is 13102200210112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21101200220131 - 21 = 21101200220129 is a prime.
It is a super-2 number, since 2×211012002201312 (a number of 27 digits) contains 22 as substring.
Together with 21101200220129, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (21101200224131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10550600110065 + 10550600110066.
It is an arithmetic number, because the mean of its divisors is an integer number (10550600110066).
Almost surely, 221101200220131 is an apocalyptic number.
21101200220131 is a deficient number, since it is larger than the sum of its proper divisors (1).
21101200220131 is an equidigital number, since it uses as much as digits as its factorization.
21101200220131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 21101200220131 its reverse (13102200210112), we get a palindrome (34203400430243).
The spelling of 21101200220131 in words is "twenty-one trillion, one hundred one billion, two hundred million, two hundred twenty thousand, one hundred thirty-one".
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