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211012103 is a prime number
BaseRepresentation
bin11001001001111…
…00101000000111
3112201001112012002
430210330220013
5413004341403
632534415515
75141400431
oct1444745007
9481045162
10211012103
11a9124575
125a80159b
1334941743
142004b651
15137d2188
hexc93ca07

211012103 has 2 divisors, whose sum is σ = 211012104. Its totient is φ = 211012102.

The previous prime is 211012069. The next prime is 211012127. The reversal of 211012103 is 301210112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 211012103 - 28 = 211011847 is a prime.

It is a super-2 number, since 2×2110121032 = 89052215224965218, which contains 22 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211012183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105506051 + 105506052.

It is an arithmetic number, because the mean of its divisors is an integer number (105506052).

Almost surely, 2211012103 is an apocalyptic number.

211012103 is a deficient number, since it is larger than the sum of its proper divisors (1).

211012103 is an equidigital number, since it uses as much as digits as its factorization.

211012103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 211012103 is about 14526.2556428007. The cubic root of 211012103 is about 595.3455639234.

Adding to 211012103 its reverse (301210112), we get a palindrome (512222215).

The spelling of 211012103 in words is "two hundred eleven million, twelve thousand, one hundred three".