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211013012303 is a prime number
BaseRepresentation
bin1100010010000101011…
…0110000101101001111
3202011122212012200020222
43010201112300231033
511424123312343203
6240534341101555
721150046003412
oct3044126605517
9664585180228
10211013012303
1181543387365
1234a8b9b78bb
1316b8ab514c2
14a2da9bbb79
155750234038
hex31215b0b4f

211013012303 has 2 divisors, whose sum is σ = 211013012304. Its totient is φ = 211013012302.

The previous prime is 211013012299. The next prime is 211013012311. The reversal of 211013012303 is 303210310112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 211013012303 - 22 = 211013012299 is a prime.

It is a super-3 number, since 3×2110130123033 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211013012333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105506506151 + 105506506152.

It is an arithmetic number, because the mean of its divisors is an integer number (105506506152).

Almost surely, 2211013012303 is an apocalyptic number.

211013012303 is a deficient number, since it is larger than the sum of its proper divisors (1).

211013012303 is an equidigital number, since it uses as much as digits as its factorization.

211013012303 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 211013012303 its reverse (303210310112), we get a palindrome (514223322415).

The spelling of 211013012303 in words is "two hundred eleven billion, thirteen million, twelve thousand, three hundred three".