Base | Representation |
---|---|
bin | 1100010010000101011… |
… | …0110000101101001111 |
3 | 202011122212012200020222 |
4 | 3010201112300231033 |
5 | 11424123312343203 |
6 | 240534341101555 |
7 | 21150046003412 |
oct | 3044126605517 |
9 | 664585180228 |
10 | 211013012303 |
11 | 81543387365 |
12 | 34a8b9b78bb |
13 | 16b8ab514c2 |
14 | a2da9bbb79 |
15 | 5750234038 |
hex | 31215b0b4f |
211013012303 has 2 divisors, whose sum is σ = 211013012304. Its totient is φ = 211013012302.
The previous prime is 211013012299. The next prime is 211013012311. The reversal of 211013012303 is 303210310112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211013012303 - 22 = 211013012299 is a prime.
It is a super-3 number, since 3×2110130123033 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211013012333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105506506151 + 105506506152.
It is an arithmetic number, because the mean of its divisors is an integer number (105506506152).
Almost surely, 2211013012303 is an apocalyptic number.
211013012303 is a deficient number, since it is larger than the sum of its proper divisors (1).
211013012303 is an equidigital number, since it uses as much as digits as its factorization.
211013012303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 211013012303 its reverse (303210310112), we get a palindrome (514223322415).
The spelling of 211013012303 in words is "two hundred eleven billion, thirteen million, twelve thousand, three hundred three".
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