Base | Representation |
---|---|
bin | 1100010010000101011… |
… | …0110000111101010011 |
3 | 202011122212012201200001 |
4 | 3010201112300331103 |
5 | 11424123312411311 |
6 | 240534341110431 |
7 | 21150046006411 |
oct | 3044126607523 |
9 | 664585181601 |
10 | 211013013331 |
11 | 8154338810a |
12 | 34a8b9b8417 |
13 | 16b8ab51b03 |
14 | a2da9bc2b1 |
15 | 57502344c1 |
hex | 31215b0f53 |
211013013331 has 2 divisors, whose sum is σ = 211013013332. Its totient is φ = 211013013330.
The previous prime is 211013013329. The next prime is 211013013371. The reversal of 211013013331 is 133310310112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211013013331 - 21 = 211013013329 is a prime.
It is a super-2 number, since 2×2110130133312 (a number of 23 digits) contains 22 as substring.
Together with 211013013329, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 211013013299 and 211013013308.
It is not a weakly prime, because it can be changed into another prime (211013013371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105506506665 + 105506506666.
It is an arithmetic number, because the mean of its divisors is an integer number (105506506666).
Almost surely, 2211013013331 is an apocalyptic number.
211013013331 is a deficient number, since it is larger than the sum of its proper divisors (1).
211013013331 is an equidigital number, since it uses as much as digits as its factorization.
211013013331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 211013013331 its reverse (133310310112), we get a palindrome (344323323443).
The spelling of 211013013331 in words is "two hundred eleven billion, thirteen million, thirteen thousand, three hundred thirty-one".
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