Base | Representation |
---|---|
bin | 11110101101010001110… |
… | …010101111110111110001 |
3 | 21110201210112211212000012 |
4 | 132231101302233313301 |
5 | 234033143001400423 |
6 | 4253225115104305 |
7 | 305312516151536 |
oct | 36552162576761 |
9 | 7421715755005 |
10 | 2110201200113 |
11 | 743a27623586 |
12 | 2a0b7a142095 |
13 | 123cb66488a6 |
14 | 741c4688d8d |
15 | 39d57aba078 |
hex | 1eb51cafdf1 |
2110201200113 has 2 divisors, whose sum is σ = 2110201200114. Its totient is φ = 2110201200112.
The previous prime is 2110201200097. The next prime is 2110201200157. The reversal of 2110201200113 is 3110021020112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1193877466609 + 916323733504 = 1092647^2 + 957248^2 .
It is a cyclic number.
It is not a de Polignac number, because 2110201200113 - 24 = 2110201200097 is a prime.
It is not a weakly prime, because it can be changed into another prime (2110201280113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055100600056 + 1055100600057.
It is an arithmetic number, because the mean of its divisors is an integer number (1055100600057).
Almost surely, 22110201200113 is an apocalyptic number.
It is an amenable number.
2110201200113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2110201200113 is an equidigital number, since it uses as much as digits as its factorization.
2110201200113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 2110201200113 its reverse (3110021020112), we get a palindrome (5220222220225).
The spelling of 2110201200113 in words is "two trillion, one hundred ten billion, two hundred one million, two hundred thousand, one hundred thirteen".
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