21102111120133 has 2 divisors, whose sum is σ = 21102111120134. Its totient is φ = 21102111120132.

The previous prime is 21102111120121. The next prime is 21102111120149. The reversal of 21102111120133 is 33102111120112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 21086849729764 + 15261390369 = 4592042^2 + 123537^2 .

It is a cyclic number.

It is not a de Polignac number, because 21102111120133 - 2¹³ = 21102111111941 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 21102111120133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21102111120833) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10551055560066 + 10551055560067.

It is an arithmetic number, because the mean of its divisors is an integer number (10551055560067).

Almost surely, 2^{21102111120133} is an apocalyptic number.

It is an amenable number.

21102111120133 is a deficient number, since it is larger than the sum of its proper divisors (1).

21102111120133 is an equidigital number, since it uses as much as digits as its factorization.

21102111120133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 21102111120133 its reverse (33102111120112), we get a palindrome (54204222240245).

The spelling of 21102111120133 in words is "twenty-one trillion, one hundred two billion, one hundred eleven million, one hundred twenty thousand, one hundred thirty-three".