211021134000122 has 4 divisors (see below), whose sum is σ = 316531701000186. Its totient is φ = 105510567000060.

The previous prime is 211021134000113. The next prime is 211021134000169. The reversal of 211021134000122 is 221000431120112.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 149478034706641 + 61543099293481 = 12226121^2 + 7844941^2 .

It is a junction number, because it is equal to n+sod(n) for n = 211021134000094 and 211021134000103.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52755283500029 + ... + 52755283500032.

Almost surely, 2^{211021134000122} is an apocalyptic number.

211021134000122 is a deficient number, since it is larger than the sum of its proper divisors (105510567000064).

211021134000122 is a wasteful number, since it uses less digits than its factorization.

211021134000122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 105510567000063.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 211021134000122 its reverse (221000431120112), we get a palindrome (432021565120234).

The spelling of 211021134000122 in words is "two hundred eleven trillion, twenty-one billion, one hundred thirty-four million, one hundred twenty-two", and thus it is an aban number.