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211022210081 is a prime number
BaseRepresentation
bin1100010010000111100…
…1110110010000100001
3202011200111111222020102
43010201321312100201
511424133141210311
6240535310152145
721150220122164
oct3044171662041
9664614458212
10211022210081
1181548599831
1234a92ab2655
1316b8ca21b87
14a2dbcd3adb
155750e4e43b
hex3121e76421

211022210081 has 2 divisors, whose sum is σ = 211022210082. Its totient is φ = 211022210080.

The previous prime is 211022209991. The next prime is 211022210083. The reversal of 211022210081 is 180012220112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 178456398481 + 32565811600 = 422441^2 + 180460^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211022210081 is a prime.

It is a super-2 number, since 2×2110222100812 (a number of 23 digits) contains 22 as substring.

Together with 211022210083, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (211022210083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105511105040 + 105511105041.

It is an arithmetic number, because the mean of its divisors is an integer number (105511105041).

Almost surely, 2211022210081 is an apocalyptic number.

It is an amenable number.

211022210081 is a deficient number, since it is larger than the sum of its proper divisors (1).

211022210081 is an equidigital number, since it uses as much as digits as its factorization.

211022210081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128, while the sum is 20.

Adding to 211022210081 its reverse (180012220112), we get a palindrome (391034430193).

The spelling of 211022210081 in words is "two hundred eleven billion, twenty-two million, two hundred ten thousand, eighty-one".