Base | Representation |
---|---|
bin | 1100010010000111110… |
… | …1010111010111010001 |
3 | 202011200120020211000202 |
4 | 3010201331113113101 |
5 | 11424133410211423 |
6 | 240535342024545 |
7 | 21150231012263 |
oct | 3044175272721 |
9 | 664616224022 |
10 | 211023132113 |
11 | 81549069542 |
12 | 34a93278155 |
13 | 16b8cc85761 |
14 | a2dc093b33 |
15 | 5751082728 |
hex | 3121f575d1 |
211023132113 has 2 divisors, whose sum is σ = 211023132114. Its totient is φ = 211023132112.
The previous prime is 211023132109. The next prime is 211023132167. The reversal of 211023132113 is 311231320112.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 152171768464 + 58851363649 = 390092^2 + 242593^2 .
It is a cyclic number.
It is not a de Polignac number, because 211023132113 - 22 = 211023132109 is a prime.
It is not a weakly prime, because it can be changed into another prime (211023137113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105511566056 + 105511566057.
It is an arithmetic number, because the mean of its divisors is an integer number (105511566057).
Almost surely, 2211023132113 is an apocalyptic number.
It is an amenable number.
211023132113 is a deficient number, since it is larger than the sum of its proper divisors (1).
211023132113 is an equidigital number, since it uses as much as digits as its factorization.
211023132113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 211023132113 its reverse (311231320112), we get a palindrome (522254452225).
The spelling of 211023132113 in words is "two hundred eleven billion, twenty-three million, one hundred thirty-two thousand, one hundred thirteen".
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