Base | Representation |
---|---|
bin | 101111111110110100101000… |
… | …110101101101110100111001 |
3 | 1000200011211012220202211220010 |
4 | 233332310220311231310321 |
5 | 210124414320202334340 |
6 | 2024451405101252133 |
7 | 62310034662305442 |
oct | 5776645065556471 |
9 | 1020154186684803 |
10 | 211025313324345 |
11 | 6126a372a53523 |
12 | 1b802152564049 |
13 | 90997a8b00c60 |
14 | 3a17972dc42c9 |
15 | 195e3bcbacb80 |
hex | bfed28d6dd39 |
211025313324345 has 32 divisors (see below), whose sum is σ = 370473467357952. Its totient is φ = 101929207940352.
The previous prime is 211025313324263. The next prime is 211025313324373. The reversal of 211025313324345 is 543423313520112.
It is a happy number.
It is not a de Polignac number, because 211025313324345 - 215 = 211025313291577 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 10209245269 + ... + 10209265938.
It is an arithmetic number, because the mean of its divisors is an integer number (11577295854936).
Almost surely, 2211025313324345 is an apocalyptic number.
It is an amenable number.
211025313324345 is a deficient number, since it is larger than the sum of its proper divisors (159448154033607).
211025313324345 is a wasteful number, since it uses less digits than its factorization.
211025313324345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20418511281.
The product of its (nonzero) digits is 259200, while the sum is 39.
Adding to 211025313324345 its reverse (543423313520112), we get a palindrome (754448626844457).
The spelling of 211025313324345 in words is "two hundred eleven trillion, twenty-five billion, three hundred thirteen million, three hundred twenty-four thousand, three hundred forty-five".
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