211031203841 has 2 divisors, whose sum is σ = 211031203842. Its totient is φ = 211031203840.

The previous prime is 211031203807. The next prime is 211031203843. The reversal of 211031203841 is 148302130112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 187204194241 + 23827009600 = 432671^2 + 154360^2 .

It is a cyclic number.

It is not a de Polignac number, because 211031203841 - 2²² = 211027009537 is a prime.

It is a super-3 number, since 3×211031203841³ (a number of 35 digits) contains 333 as substring.

Together with 211031203843, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 211031203841.

It is not a weakly prime, because it can be changed into another prime (211031203843) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105515601920 + 105515601921.

It is an arithmetic number, because the mean of its divisors is an integer number (105515601921).

Almost surely, 2^211031203841 is an apocalyptic number.

It is an amenable number.

211031203841 is a deficient number, since it is larger than the sum of its proper divisors (1).

211031203841 is an equidigital number, since it uses as much as digits as its factorization.

211031203841 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 211031203841 its reverse (148302130112), we get a palindrome (359333333953).

The spelling of 211031203841 in words is "two hundred eleven billion, thirty-one million, two hundred three thousand, eight hundred forty-one".