Base | Representation |
---|---|
bin | 101111111110111011111010… |
… | …010101010011010111100111 |
3 | 1000200012120101012001222121211 |
4 | 233332323322111103113213 |
5 | 210130031313442310043 |
6 | 2024455140042052251 |
7 | 62310432342451366 |
oct | 5776737225232747 |
9 | 1020176335058554 |
10 | 211033123010023 |
11 | 61272710353a06 |
12 | 1b803771aaa087 |
13 | 909a451a9b542 |
14 | 3a180b42ab7dd |
15 | 195e6c8613a9d |
hex | bfeefa5535e7 |
211033123010023 has 2 divisors, whose sum is σ = 211033123010024. Its totient is φ = 211033123010022.
The previous prime is 211033123009979. The next prime is 211033123010041. The reversal of 211033123010023 is 320010321330112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211033123010023 - 233 = 211024533075431 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 211033123009976 and 211033123010003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211033123010093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105516561505011 + 105516561505012.
It is an arithmetic number, because the mean of its divisors is an integer number (105516561505012).
Almost surely, 2211033123010023 is an apocalyptic number.
211033123010023 is a deficient number, since it is larger than the sum of its proper divisors (1).
211033123010023 is an equidigital number, since it uses as much as digits as its factorization.
211033123010023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 211033123010023 its reverse (320010321330112), we get a palindrome (531043444340135).
The spelling of 211033123010023 in words is "two hundred eleven trillion, thirty-three billion, one hundred twenty-three million, ten thousand, twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •