211040113 has 2 divisors, whose sum is σ = 211040114. Its totient is φ = 211040112.

The previous prime is 211040077. The next prime is 211040129. The reversal of 211040113 is 311040112.

211040113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 189667984 + 21372129 = 13772^2 + 4623^2 .

It is a cyclic number.

It is not a de Polignac number, because 211040113 - 2¹³ = 211031921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211040093 and 211040102.

It is not a weakly prime, because it can be changed into another prime (211040183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105520056 + 105520057.

It is an arithmetic number, because the mean of its divisors is an integer number (105520057).

Almost surely, 2^211040113 is an apocalyptic number.

It is an amenable number.

211040113 is a deficient number, since it is larger than the sum of its proper divisors (1).

211040113 is an equidigital number, since it uses as much as digits as its factorization.

211040113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 211040113 is about 14527.2197271192. The cubic root of 211040113 is about 595.3719050530.

Adding to 211040113 its reverse (311040112), we get a palindrome (522080225).

Subtracting 211040113 from its reverse (311040112), we obtain a palindrome (99999999).

The spelling of 211040113 in words is "two hundred eleven million, forty thousand, one hundred thirteen".