Base | Representation |
---|---|
bin | 101111111111000101001101… |
… | …000101100111000111100011 |
3 | 1000200020112010121001200020121 |
4 | 233333011031011213013203 |
5 | 210130212232420341011 |
6 | 2024503510132221111 |
7 | 62311234535040664 |
oct | 5777051505470743 |
9 | 1020215117050217 |
10 | 211043101340131 |
11 | 61276970908015 |
12 | 1b80569776a797 |
13 | 909b38213c498 |
14 | 3a1877d5cd36b |
15 | 195eaae640e71 |
hex | bff14d1671e3 |
211043101340131 has 2 divisors, whose sum is σ = 211043101340132. Its totient is φ = 211043101340130.
The previous prime is 211043101340077. The next prime is 211043101340179. The reversal of 211043101340131 is 131043101340112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211043101340131 is a prime.
It is a super-2 number, since 2×2110431013401312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 211043101340096 and 211043101340105.
It is not a weakly prime, because it can be changed into another prime (211043101340191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105521550670065 + 105521550670066.
It is an arithmetic number, because the mean of its divisors is an integer number (105521550670066).
Almost surely, 2211043101340131 is an apocalyptic number.
211043101340131 is a deficient number, since it is larger than the sum of its proper divisors (1).
211043101340131 is an equidigital number, since it uses as much as digits as its factorization.
211043101340131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 211043101340131 its reverse (131043101340112), we get a palindrome (342086202680243).
The spelling of 211043101340131 in words is "two hundred eleven trillion, forty-three billion, one hundred one million, three hundred forty thousand, one hundred thirty-one".
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