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21105025232 = 241319064077
BaseRepresentation
bin10011101001111101…
…010010000011010000
32000110211211100220012
4103221331102003100
5321210341301412
613410121534052
71345000516544
oct235175220320
960424740805
1021105025232
118a50266915
124110044328
131cb45c7a15
141042d71a24
15837c95c22
hex4e9f520d0

21105025232 has 10 divisors (see below), whose sum is σ = 40890986418. Its totient is φ = 10552512608.

The previous prime is 21105025231. The next prime is 21105025247. The reversal of 21105025232 is 23252050112.

It can be written as a sum of positive squares in only one way, i.e., 11338842256 + 9766182976 = 106484^2 + 98824^2 .

It is a super-3 number, since 3×211050252323 (a number of 32 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21105025198 and 21105025207.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21105025231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 659532023 + ... + 659532054.

Almost surely, 221105025232 is an apocalyptic number.

It is an amenable number.

21105025232 is a deficient number, since it is larger than the sum of its proper divisors (19785961186).

21105025232 is a wasteful number, since it uses less digits than its factorization.

21105025232 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1319064085 (or 1319064079 counting only the distinct ones).

The product of its (nonzero) digits is 1200, while the sum is 23.

Adding to 21105025232 its reverse (23252050112), we get a palindrome (44357075344).

The spelling of 21105025232 in words is "twenty-one billion, one hundred five million, twenty-five thousand, two hundred thirty-two".

Divisors: 1 2 4 8 16 1319064077 2638128154 5276256308 10552512616 21105025232