Base | Representation |
---|---|
bin | 10011101001111110… |
… | …110001010010000111 |
3 | 2000110212120011222021 |
4 | 103221332301102013 |
5 | 321210441242203 |
6 | 13410134144011 |
7 | 1345004033020 |
oct | 235176612207 |
9 | 60425504867 |
10 | 21105415303 |
11 | 8a50502995 |
12 | 41101b2007 |
13 | 1cb470342b |
14 | 1043033c47 |
15 | 837d215bd |
hex | 4e9fb1487 |
21105415303 has 16 divisors (see below), whose sum is σ = 24276925440. Its totient is φ = 17973367776.
The previous prime is 21105415301. The next prime is 21105415337. The reversal of 21105415303 is 30351450112.
It is a happy number.
It is not a de Polignac number, because 21105415303 - 21 = 21105415301 is a prime.
It is a super-2 number, since 2×211054153032 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21105415301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 726901 + ... + 755377.
It is an arithmetic number, because the mean of its divisors is an integer number (1517307840).
Almost surely, 221105415303 is an apocalyptic number.
21105415303 is a deficient number, since it is larger than the sum of its proper divisors (3171510137).
21105415303 is a wasteful number, since it uses less digits than its factorization.
21105415303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29166.
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 21105415303 its reverse (30351450112), we get a palindrome (51456865415).
The spelling of 21105415303 in words is "twenty-one billion, one hundred five million, four hundred fifteen thousand, three hundred three".
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