Base | Representation |
---|---|
bin | 11110101110000001011… |
… | …101110101001010101011 |
3 | 21110210212021212001221112 |
4 | 132232001131311022223 |
5 | 234041312230220042 |
6 | 4253440330100535 |
7 | 305341400430242 |
oct | 36560135651253 |
9 | 7423767761845 |
10 | 2111001023147 |
11 | 7442a8053455 |
12 | 2a1161b7a74b |
13 | 1240b3269063 |
14 | 7425c9a9959 |
15 | 39da2e09982 |
hex | 1eb817752ab |
2111001023147 has 2 divisors, whose sum is σ = 2111001023148. Its totient is φ = 2111001023146.
The previous prime is 2111001023077. The next prime is 2111001023149. The reversal of 2111001023147 is 7413201001112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2111001023147 - 230 = 2109927281323 is a prime.
Together with 2111001023149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2111001023149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055500511573 + 1055500511574.
It is an arithmetic number, because the mean of its divisors is an integer number (1055500511574).
Almost surely, 22111001023147 is an apocalyptic number.
2111001023147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111001023147 is an equidigital number, since it uses as much as digits as its factorization.
2111001023147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 336, while the sum is 23.
Adding to 2111001023147 its reverse (7413201001112), we get a palindrome (9524202024259).
The spelling of 2111001023147 in words is "two trillion, one hundred eleven billion, one million, twenty-three thousand, one hundred forty-seven".
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