2111002010113 has 2 divisors, whose sum is σ = 2111002010114. Its totient is φ = 2111002010112.

The previous prime is 2111002010077. The next prime is 2111002010123. The reversal of 2111002010113 is 3110102001112.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1744362072049 + 366639938064 = 1320743^2 + 605508^2 .

It is a cyclic number.

It is not a de Polignac number, because 2111002010113 - 2¹³ = 2111002001921 is a prime.

It is a super-2 number, since 2×2111002010113² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2111002010093 and 2111002010102.

It is not a weakly prime, because it can be changed into another prime (2111002010123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055501005056 + 1055501005057.

It is an arithmetic number, because the mean of its divisors is an integer number (1055501005057).

Almost surely, 2^{2111002010113} is an apocalyptic number.

It is an amenable number.

2111002010113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111002010113 is an equidigital number, since it uses as much as digits as its factorization.

2111002010113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 2111002010113 its reverse (3110102001112), we get a palindrome (5221104011225).

Subtracting 2111002010113 from its reverse (3110102001112), we obtain a palindrome (999099990999).

The spelling of 2111002010113 in words is "two trillion, one hundred eleven billion, two million, ten thousand, one hundred thirteen".