Base | Representation |
---|---|
bin | 11110101110000001100… |
… | …001101000110101101111 |
3 | 21110210212100201210001121 |
4 | 132232001201220311233 |
5 | 234041313004134411 |
6 | 4253440403321411 |
7 | 305341412055145 |
oct | 36560141506557 |
9 | 7423770653047 |
10 | 2111002021231 |
11 | 7442a8675314 |
12 | 2a1162380267 |
13 | 1240b352843c |
14 | 7425cb89595 |
15 | 39da3055571 |
hex | 1eb81868d6f |
2111002021231 has 2 divisors, whose sum is σ = 2111002021232. Its totient is φ = 2111002021230.
The previous prime is 2111002021213. The next prime is 2111002021237. The reversal of 2111002021231 is 1321202001112.
Together with previous prime (2111002021213) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2111002021231 - 215 = 2111001988463 is a prime.
It is a super-2 number, since 2×21110020212312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2111002021237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055501010615 + 1055501010616.
It is an arithmetic number, because the mean of its divisors is an integer number (1055501010616).
Almost surely, 22111002021231 is an apocalyptic number.
2111002021231 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111002021231 is an equidigital number, since it uses as much as digits as its factorization.
2111002021231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 2111002021231 its reverse (1321202001112), we get a palindrome (3432204022343).
The spelling of 2111002021231 in words is "two trillion, one hundred eleven billion, two million, twenty-one thousand, two hundred thirty-one".
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