Base | Representation |
---|---|
bin | 11110101110000001100… |
… | …101011101000000011101 |
3 | 21110210212102121120221201 |
4 | 132232001211131000131 |
5 | 234041313233140331 |
6 | 4253440440555501 |
7 | 305341423422004 |
oct | 36560145350035 |
9 | 7423772546851 |
10 | 2111003021341 |
11 | 7442a9198755 |
12 | 2a1162782b91 |
13 | 1240b37b8716 |
14 | 7425cd69c3b |
15 | 39da31a1a61 |
hex | 1eb8195d01d |
2111003021341 has 2 divisors, whose sum is σ = 2111003021342. Its totient is φ = 2111003021340.
The previous prime is 2111003021279. The next prime is 2111003021383. The reversal of 2111003021341 is 1431203001112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1180895156100 + 930107865241 = 1086690^2 + 964421^2 .
It is a cyclic number.
It is not a de Polignac number, because 2111003021341 - 225 = 2110969466909 is a prime.
It is a super-2 number, since 2×21110030213412 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2111003091341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055501510670 + 1055501510671.
It is an arithmetic number, because the mean of its divisors is an integer number (1055501510671).
Almost surely, 22111003021341 is an apocalyptic number.
It is an amenable number.
2111003021341 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111003021341 is an equidigital number, since it uses as much as digits as its factorization.
2111003021341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 2111003021341 its reverse (1431203001112), we get a palindrome (3542206022453).
The spelling of 2111003021341 in words is "two trillion, one hundred eleven billion, three million, twenty-one thousand, three hundred forty-one".
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