Base | Representation |
---|---|
bin | 11110101110000001101… |
… | …001010011101111111001 |
3 | 21110210212111111221022021 |
4 | 132232001221103233321 |
5 | 234041314013010433 |
6 | 4253440514354441 |
7 | 305341435131343 |
oct | 36560151235771 |
9 | 7423774457267 |
10 | 2111004031993 |
11 | 7442a9818aaa |
12 | 2a1162b8ba21 |
13 | 1240b3a8073c |
14 | 7425d150293 |
15 | 39da330122d |
hex | 1eb81a53bf9 |
2111004031993 has 2 divisors, whose sum is σ = 2111004031994. Its totient is φ = 2111004031992.
The previous prime is 2111004031957. The next prime is 2111004032099. The reversal of 2111004031993 is 3991304001112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1625183879929 + 485820152064 = 1274827^2 + 697008^2 .
It is a cyclic number.
It is not a de Polignac number, because 2111004031993 - 229 = 2110467161081 is a prime.
It is not a weakly prime, because it can be changed into another prime (2111004091993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055502015996 + 1055502015997.
It is an arithmetic number, because the mean of its divisors is an integer number (1055502015997).
Almost surely, 22111004031993 is an apocalyptic number.
It is an amenable number.
2111004031993 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111004031993 is an equidigital number, since it uses as much as digits as its factorization.
2111004031993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 34.
The spelling of 2111004031993 in words is "two trillion, one hundred eleven billion, four million, thirty-one thousand, nine hundred ninety-three".
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