Base | Representation |
---|---|
bin | 11110101110000010000… |
… | …000001110101010100011 |
3 | 21110210212220211012101221 |
4 | 132232002000032222203 |
5 | 234041322032243413 |
6 | 4253441251235511 |
7 | 305341540164661 |
oct | 36560200165243 |
9 | 7423786735357 |
10 | 2111010040483 |
11 | 7443021522a3 |
12 | 2a1164ba8b97 |
13 | 1240b50a5566 |
14 | 7425dc75c31 |
15 | 39da3adb68d |
hex | 1eb8200eaa3 |
2111010040483 has 2 divisors, whose sum is σ = 2111010040484. Its totient is φ = 2111010040482.
The previous prime is 2111010040369. The next prime is 2111010040507. The reversal of 2111010040483 is 3840400101112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2111010040483 is a prime.
It is not a weakly prime, because it can be changed into another prime (2111010040583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055505020241 + 1055505020242.
It is an arithmetic number, because the mean of its divisors is an integer number (1055505020242).
Almost surely, 22111010040483 is an apocalyptic number.
2111010040483 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111010040483 is an equidigital number, since it uses as much as digits as its factorization.
2111010040483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 2111010040483 its reverse (3840400101112), we get a palindrome (5951410141595).
The spelling of 2111010040483 in words is "two trillion, one hundred eleven billion, ten million, forty thousand, four hundred eighty-three".
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