Base | Representation |
---|---|
bin | 11110101110000010000… |
… | …000111000000100110001 |
3 | 21110210212221010211001221 |
4 | 132232002000320010301 |
5 | 234041322103210342 |
6 | 4253441255025041 |
7 | 305341541502325 |
oct | 36560200700461 |
9 | 7423787124057 |
10 | 2111010210097 |
11 | 744302258778 |
12 | 2a116506b181 |
13 | 1240b5134819 |
14 | 7425dcbb985 |
15 | 39da3b21a67 |
hex | 1eb82038131 |
2111010210097 has 2 divisors, whose sum is σ = 2111010210098. Its totient is φ = 2111010210096.
The previous prime is 2111010210079. The next prime is 2111010210149. The reversal of 2111010210097 is 7900120101112.
Together with previous prime (2111010210079) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2043501699121 + 67508510976 = 1429511^2 + 259824^2 .
It is a cyclic number.
It is not a de Polignac number, because 2111010210097 - 235 = 2076650471729 is a prime.
It is not a weakly prime, because it can be changed into another prime (2111010210047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055505105048 + 1055505105049.
It is an arithmetic number, because the mean of its divisors is an integer number (1055505105049).
Almost surely, 22111010210097 is an apocalyptic number.
It is an amenable number.
2111010210097 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111010210097 is an equidigital number, since it uses as much as digits as its factorization.
2111010210097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 25.
The spelling of 2111010210097 in words is "two trillion, one hundred eleven billion, ten million, two hundred ten thousand, ninety-seven".
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