Base | Representation |
---|---|
bin | 11110101110000010001… |
… | …000000101101111101111 |
3 | 21110210220001200220001012 |
4 | 132232002020011233233 |
5 | 234041323044213403 |
6 | 4253441403335435 |
7 | 305341563536423 |
oct | 36560210055757 |
9 | 7423801626035 |
10 | 2111012101103 |
11 | 74430332a494 |
12 | 2a116582157b |
13 | 1240b5647469 |
14 | 74260250b83 |
15 | 39da3d96ed8 |
hex | 1eb82205bef |
2111012101103 has 2 divisors, whose sum is σ = 2111012101104. Its totient is φ = 2111012101102.
The previous prime is 2111012101087. The next prime is 2111012101127. The reversal of 2111012101103 is 3011012101112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2111012101103 - 24 = 2111012101087 is a prime.
It is a super-3 number, since 3×21110121011033 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2111012101603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055506050551 + 1055506050552.
It is an arithmetic number, because the mean of its divisors is an integer number (1055506050552).
Almost surely, 22111012101103 is an apocalyptic number.
2111012101103 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111012101103 is an equidigital number, since it uses as much as digits as its factorization.
2111012101103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 2111012101103 its reverse (3011012101112), we get a palindrome (5122024202215).
Subtracting 2111012101103 from its reverse (3011012101112), we obtain a palindrome (900000000009).
The spelling of 2111012101103 in words is "two trillion, one hundred eleven billion, twelve million, one hundred one thousand, one hundred three".
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