Base | Representation |
---|---|
bin | 1100010010011010101… |
… | …0010001011001101010 |
3 | 202011220001200101022100 |
4 | 3010212222101121222 |
5 | 11424314103404114 |
6 | 240551240434230 |
7 | 21152206334643 |
oct | 3044652213152 |
9 | 664801611270 |
10 | 211102013034 |
11 | 81589645990 |
12 | 34ab5778976 |
13 | 16ba3413663 |
14 | a3087486ca |
15 | 5757e64909 |
hex | 3126a9166a |
211102013034 has 24 divisors (see below), whose sum is σ = 498968394912. Its totient is φ = 63970306920.
The previous prime is 211102013033. The next prime is 211102013051. The reversal of 211102013034 is 430310201112.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 211102012998 and 211102013016.
It is not an unprimeable number, because it can be changed into a prime (211102013033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 533085694 + ... + 533086089.
It is an arithmetic number, because the mean of its divisors is an integer number (20790349788).
Almost surely, 2211102013034 is an apocalyptic number.
211102013034 is an abundant number, since it is smaller than the sum of its proper divisors (287866381878).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211102013034 is a wasteful number, since it uses less digits than its factorization.
211102013034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1066171802 (or 1066171799 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 211102013034 its reverse (430310201112), we get a palindrome (641412214146).
The spelling of 211102013034 in words is "two hundred eleven billion, one hundred two million, thirteen thousand, thirty-four".
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