Base | Representation |
---|---|
bin | 101111111111111100001111… |
… | …101101110011111010010011 |
3 | 1000200110011200100221022012021 |
4 | 233333330033231303322103 |
5 | 210132144302003424133 |
6 | 2024551002404112311 |
7 | 62315426224612531 |
oct | 5777741755637223 |
9 | 1020404610838167 |
10 | 211102201233043 |
11 | 61299a3919a31a |
12 | 1b815030095697 |
13 | 90a3b10266313 |
14 | 3a1b5886d9151 |
15 | 19613bcd4552d |
hex | bfff0fb73e93 |
211102201233043 has 2 divisors, whose sum is σ = 211102201233044. Its totient is φ = 211102201233042.
The previous prime is 211102201232959. The next prime is 211102201233047. The reversal of 211102201233043 is 340332102201112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211102201233043 - 217 = 211102201101971 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 211102201232999 and 211102201233017.
It is not a weakly prime, because it can be changed into another prime (211102201233047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105551100616521 + 105551100616522.
It is an arithmetic number, because the mean of its divisors is an integer number (105551100616522).
Almost surely, 2211102201233043 is an apocalyptic number.
211102201233043 is a deficient number, since it is larger than the sum of its proper divisors (1).
211102201233043 is an equidigital number, since it uses as much as digits as its factorization.
211102201233043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 211102201233043 its reverse (340332102201112), we get a palindrome (551434303434155).
The spelling of 211102201233043 in words is "two hundred eleven trillion, one hundred two billion, two hundred one million, two hundred thirty-three thousand, forty-three".
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