Base | Representation |
---|---|
bin | 1100010010011100100… |
… | …0110001100001111001 |
3 | 202011220121201121122111 |
4 | 3010213020301201321 |
5 | 11424323130241303 |
6 | 240552124052321 |
7 | 21152334316444 |
oct | 3044710614171 |
9 | 664817647574 |
10 | 211110008953 |
11 | 81593107388 |
12 | 34ab83940a1 |
13 | 16ba4c82c7c |
14 | a30982a65b |
15 | 57589e3b6d |
hex | 3127231879 |
211110008953 has 2 divisors, whose sum is σ = 211110008954. Its totient is φ = 211110008952.
The previous prime is 211110008951. The next prime is 211110008987. The reversal of 211110008953 is 359800011112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 200607243664 + 10502765289 = 447892^2 + 102483^2 .
It is a cyclic number.
It is not a de Polignac number, because 211110008953 - 21 = 211110008951 is a prime.
Together with 211110008951, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (211110008951) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105555004476 + 105555004477.
It is an arithmetic number, because the mean of its divisors is an integer number (105555004477).
Almost surely, 2211110008953 is an apocalyptic number.
It is an amenable number.
211110008953 is a deficient number, since it is larger than the sum of its proper divisors (1).
211110008953 is an equidigital number, since it uses as much as digits as its factorization.
211110008953 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2160, while the sum is 31.
The spelling of 211110008953 in words is "two hundred eleven billion, one hundred ten million, eight thousand, nine hundred fifty-three".
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