2111100113 has 2 divisors, whose sum is σ = 2111100114. Its totient is φ = 2111100112.

The previous prime is 2111100107. The next prime is 2111100133. The reversal of 2111100113 is 3110011112.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1454049424 + 657050689 = 38132^2 + 25633^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2111100113 is a prime.

It is a super-2 number, since 2×2111100113² = 8913487374217225538, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2111100094 and 2111100103.

It is not a weakly prime, because it can be changed into another prime (2111100133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055550056 + 1055550057.

It is an arithmetic number, because the mean of its divisors is an integer number (1055550057).

Almost surely, 2^2111100113 is an apocalyptic number.

It is an amenable number.

2111100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111100113 is an equidigital number, since it uses as much as digits as its factorization.

2111100113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 11.

The square root of 2111100113 is about 45946.7094904521. The cubic root of 2111100113 is about 1282.8314827247.

Adding to 2111100113 its reverse (3110011112), we get a palindrome (5221111225).

The spelling of 2111100113 in words is "two billion, one hundred eleven million, one hundred thousand, one hundred thirteen".