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211110012110113 is a prime number
BaseRepresentation
bin110000000000000011100001…
…010001111100010100100001
31000200110220211201110222012121
4300000003201101330110201
5210132311301100010423
62024554333430224241
762316123621150064
oct6000034121742441
91020426751428177
10211110012110113
11612a2287233926
121b81664bab5081
1390a478655cc7c
143a1bac9c128db
1519616c893445d
hexc000e147c521

211110012110113 has 2 divisors, whose sum is σ = 211110012110114. Its totient is φ = 211110012110112.

The previous prime is 211110012110111. The next prime is 211110012110167. The reversal of 211110012110113 is 311011210011112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 193203133461009 + 17906878649104 = 13899753^2 + 4231652^2 .

It is a cyclic number.

It is not a de Polignac number, because 211110012110113 - 21 = 211110012110111 is a prime.

Together with 211110012110111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (211110012110111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105555006055056 + 105555006055057.

It is an arithmetic number, because the mean of its divisors is an integer number (105555006055057).

Almost surely, 2211110012110113 is an apocalyptic number.

It is an amenable number.

211110012110113 is a deficient number, since it is larger than the sum of its proper divisors (1).

211110012110113 is an equidigital number, since it uses as much as digits as its factorization.

211110012110113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 16.

Adding to 211110012110113 its reverse (311011210011112), we get a palindrome (522121222121225).

The spelling of 211110012110113 in words is "two hundred eleven trillion, one hundred ten billion, twelve million, one hundred ten thousand, one hundred thirteen".