Base | Representation |
---|---|
bin | 1001100110011010010100… |
… | …10100010110110011001101 |
3 | 2202202012012122212121210211 |
4 | 10303031022110112303031 |
5 | 10231340322321010333 |
6 | 112522133054002421 |
7 | 4306135351444132 |
oct | 463151224266315 |
9 | 82665178777724 |
10 | 21111011110093 |
11 | 67aa147455013 |
12 | 244b556aa6411 |
13 | ba19b53a6568 |
14 | 52dac7c88589 |
15 | 26922c36cecd |
hex | 13334a516ccd |
21111011110093 has 2 divisors, whose sum is σ = 21111011110094. Its totient is φ = 21111011110092.
The previous prime is 21111011110051. The next prime is 21111011110139. The reversal of 21111011110093 is 39001111011112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11380117674249 + 9730893435844 = 3373443^2 + 3119438^2 .
It is a cyclic number.
It is not a de Polignac number, because 21111011110093 - 217 = 21111010979021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21111011110793) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10555505555046 + 10555505555047.
It is an arithmetic number, because the mean of its divisors is an integer number (10555505555047).
Almost surely, 221111011110093 is an apocalyptic number.
It is an amenable number.
21111011110093 is a deficient number, since it is larger than the sum of its proper divisors (1).
21111011110093 is an equidigital number, since it uses as much as digits as its factorization.
21111011110093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 22.
The spelling of 21111011110093 in words is "twenty-one trillion, one hundred eleven billion, eleven million, one hundred ten thousand, ninety-three".
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