Base | Representation |
---|---|
bin | 11110101110000111011… |
… | …011101010111011010011 |
3 | 21110211010021012112022012 |
4 | 132232013123222323103 |
5 | 234042013341321321 |
6 | 4253454303333135 |
7 | 305344024305356 |
oct | 36560733527323 |
9 | 7424107175265 |
10 | 2111101120211 |
11 | 7443496008a6 |
12 | 2a118b5b11ab |
13 | 1240cac14aa5 |
14 | 7426bdc429d |
15 | 39dabacd05b |
hex | 1eb876eaed3 |
2111101120211 has 2 divisors, whose sum is σ = 2111101120212. Its totient is φ = 2111101120210.
The previous prime is 2111101120207. The next prime is 2111101120213. The reversal of 2111101120211 is 1120211011112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2111101120211 - 22 = 2111101120207 is a prime.
It is a super-2 number, since 2×21111011202112 (a number of 25 digits) contains 22 as substring.
Together with 2111101120213, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2111101120213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055550560105 + 1055550560106.
It is an arithmetic number, because the mean of its divisors is an integer number (1055550560106).
Almost surely, 22111101120211 is an apocalyptic number.
2111101120211 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111101120211 is an equidigital number, since it uses as much as digits as its factorization.
2111101120211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 14.
Adding to 2111101120211 its reverse (1120211011112), we get a palindrome (3231312131323).
The spelling of 2111101120211 in words is "two trillion, one hundred eleven billion, one hundred one million, one hundred twenty thousand, two hundred eleven".
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