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2111102119993 is a prime number
BaseRepresentation
bin11110101110000111011…
…111011111000000111001
321110211010100002022202011
4132232013133133000321
5234042014120314433
64253454341005521
7305344035641236
oct36560737370071
97424110068664
102111102119993
1174434a123a69
122a118b9b38a1
131240cb1a4b89
147426c1a478d
1539dabc293cd
hex1eb877df039

2111102119993 has 2 divisors, whose sum is σ = 2111102119994. Its totient is φ = 2111102119992.

The previous prime is 2111102119991. The next prime is 2111102120003. The reversal of 2111102119993 is 3999112011112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1796007383104 + 315094736889 = 1340152^2 + 561333^2 .

It is a cyclic number.

It is not a de Polignac number, because 2111102119993 - 21 = 2111102119991 is a prime.

It is a super-2 number, since 2×21111021199932 (a number of 25 digits) contains 22 as substring.

Together with 2111102119991, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (2111102119991) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055551059996 + 1055551059997.

It is an arithmetic number, because the mean of its divisors is an integer number (1055551059997).

Almost surely, 22111102119993 is an apocalyptic number.

It is an amenable number.

2111102119993 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111102119993 is an equidigital number, since it uses as much as digits as its factorization.

2111102119993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8748, while the sum is 40.

The spelling of 2111102119993 in words is "two trillion, one hundred eleven billion, one hundred two million, one hundred nineteen thousand, nine hundred ninety-three".