Base | Representation |
---|---|
bin | 11110101110001000000… |
… | …001110001110111010111 |
3 | 21110211010222000001212012 |
4 | 132232020001301313113 |
5 | 234042023421010403 |
6 | 4253455301414435 |
7 | 305344205233412 |
oct | 36561001616727 |
9 | 7424128001765 |
10 | 2111111110103 |
11 | 744354204406 |
12 | 2a1192a0a41b |
13 | 124100001b78 |
14 | 7426d464b79 |
15 | 39dac902ed8 |
hex | 1eb88071dd7 |
2111111110103 has 2 divisors, whose sum is σ = 2111111110104. Its totient is φ = 2111111110102.
The previous prime is 2111111110091. The next prime is 2111111110153. The reversal of 2111111110103 is 3010111111112.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2111111110103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2111111110153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055555555051 + 1055555555052.
It is an arithmetic number, because the mean of its divisors is an integer number (1055555555052).
Almost surely, 22111111110103 is an apocalyptic number.
2111111110103 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111111110103 is an equidigital number, since it uses as much as digits as its factorization.
2111111110103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 14.
Adding to 2111111110103 its reverse (3010111111112), we get a palindrome (5121222221215).
The spelling of 2111111110103 in words is "two trillion, one hundred eleven billion, one hundred eleven million, one hundred ten thousand, one hundred three".
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