Base | Representation |
---|---|
bin | 1100010010011101000… |
… | …0011111101101101011 |
3 | 202011220202112110022001 |
4 | 3010213100133231223 |
5 | 11424324140030011 |
6 | 240552235311431 |
7 | 21152360450026 |
oct | 3044720375553 |
9 | 664822473261 |
10 | 211112033131 |
11 | 8159426a15a |
12 | 34ab8bab577 |
13 | 16ba55113cc |
14 | a309bd61bd |
15 | 5758c937c1 |
hex | 312741fb6b |
211112033131 has 2 divisors, whose sum is σ = 211112033132. Its totient is φ = 211112033130.
The previous prime is 211112033129. The next prime is 211112033159. The reversal of 211112033131 is 131330211112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211112033131 - 21 = 211112033129 is a prime.
It is a super-2 number, since 2×2111120331312 (a number of 23 digits) contains 22 as substring.
Together with 211112033129, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 211112033099 and 211112033108.
It is not a weakly prime, because it can be changed into another prime (211112033731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105556016565 + 105556016566.
It is an arithmetic number, because the mean of its divisors is an integer number (105556016566).
Almost surely, 2211112033131 is an apocalyptic number.
211112033131 is a deficient number, since it is larger than the sum of its proper divisors (1).
211112033131 is an equidigital number, since it uses as much as digits as its factorization.
211112033131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 211112033131 its reverse (131330211112), we get a palindrome (342442244243).
The spelling of 211112033131 in words is "two hundred eleven billion, one hundred twelve million, thirty-three thousand, one hundred thirty-one".
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