Base | Representation |
---|---|
bin | 11110101110001000100… |
… | …111100000011100010101 |
3 | 21110211011122121112112120 |
4 | 132232020213200130111 |
5 | 234042033434001323 |
6 | 4253500253410153 |
7 | 305344355264511 |
oct | 36561047403425 |
9 | 7424148545476 |
10 | 2111121000213 |
11 | 744359849a55 |
12 | 2a1196199959 |
13 | 1241020856c4 |
14 | 742708bb141 |
15 | 39dad7085e3 |
hex | 1eb889e0715 |
2111121000213 has 8 divisors (see below), whose sum is σ = 2817668395776. Its totient is φ = 1405993802400.
The previous prime is 2111121000203. The next prime is 2111121000217. The reversal of 2111121000213 is 3120001211112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2111121000213 - 217 = 2111120869141 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2111121000192 and 2111121000201.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2111121000217) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 355045968 + ... + 355051913.
It is an arithmetic number, because the mean of its divisors is an integer number (352208549472).
Almost surely, 22111121000213 is an apocalyptic number.
It is an amenable number.
2111121000213 is a deficient number, since it is larger than the sum of its proper divisors (706547395563).
2111121000213 is an equidigital number, since it uses as much as digits as its factorization.
2111121000213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 710098875.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 2111121000213 its reverse (3120001211112), we get a palindrome (5231122211325).
The spelling of 2111121000213 in words is "two trillion, one hundred eleven billion, one hundred twenty-one million, two hundred thirteen", and thus it is an aban number.
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