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2111121000213 = 3991710097881
BaseRepresentation
bin11110101110001000100…
…111100000011100010101
321110211011122121112112120
4132232020213200130111
5234042033434001323
64253500253410153
7305344355264511
oct36561047403425
97424148545476
102111121000213
11744359849a55
122a1196199959
131241020856c4
14742708bb141
1539dad7085e3
hex1eb889e0715

2111121000213 has 8 divisors (see below), whose sum is σ = 2817668395776. Its totient is φ = 1405993802400.

The previous prime is 2111121000203. The next prime is 2111121000217. The reversal of 2111121000213 is 3120001211112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2111121000213 - 217 = 2111120869141 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2111121000192 and 2111121000201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2111121000217) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 355045968 + ... + 355051913.

It is an arithmetic number, because the mean of its divisors is an integer number (352208549472).

Almost surely, 22111121000213 is an apocalyptic number.

It is an amenable number.

2111121000213 is a deficient number, since it is larger than the sum of its proper divisors (706547395563).

2111121000213 is an equidigital number, since it uses as much as digits as its factorization.

2111121000213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 710098875.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 2111121000213 its reverse (3120001211112), we get a palindrome (5231122211325).

The spelling of 2111121000213 in words is "two trillion, one hundred eleven billion, one hundred twenty-one million, two hundred thirteen", and thus it is an aban number.

Divisors: 1 3 991 2973 710097881 2130293643 703707000071 2111121000213