211112134100033 has 2 divisors, whose sum is σ = 211112134100034. Its totient is φ = 211112134100032.

The previous prime is 211112134099991. The next prime is 211112134100057. The reversal of 211112134100033 is 330001431211112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 194068637445904 + 17043496654129 = 13930852^2 + 4128377^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-211112134100033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211112134099981 and 211112134100008.

It is not a weakly prime, because it can be changed into another prime (211112184100033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105556067050016 + 105556067050017.

It is an arithmetic number, because the mean of its divisors is an integer number (105556067050017).

Almost surely, 2^{211112134100033} is an apocalyptic number.

It is an amenable number.

211112134100033 is a deficient number, since it is larger than the sum of its proper divisors (1).

211112134100033 is an equidigital number, since it uses as much as digits as its factorization.

211112134100033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 211112134100033 its reverse (330001431211112), we get a palindrome (541113565311145).

The spelling of 211112134100033 in words is "two hundred eleven trillion, one hundred twelve billion, one hundred thirty-four million, one hundred thousand, thirty-three".