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211112134100057 is a prime number
BaseRepresentation
bin110000000000000101011111…
…110000101100010001011001
31000200111010022121101020011202
4300000011133300230101121
5210132330122312200212
62024555324152003545
762316230325601511
oct6000053760542131
91020433277336152
10211112134100057
11612a3176021323
121b816b426905b5
1390a4a34079c18
143a1bc4b984841
15196179ed920c2
hexc0015fc2c459

211112134100057 has 2 divisors, whose sum is σ = 211112134100058. Its totient is φ = 211112134100056.

The previous prime is 211112134100033. The next prime is 211112134100149. The reversal of 211112134100057 is 750001431211112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 138009958999696 + 73102175100361 = 11747764^2 + 8549981^2 .

It is a cyclic number.

It is not a de Polignac number, because 211112134100057 - 216 = 211112134034521 is a prime.

It is not a weakly prime, because it can be changed into another prime (211112134120057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105556067050028 + 105556067050029.

It is an arithmetic number, because the mean of its divisors is an integer number (105556067050029).

Almost surely, 2211112134100057 is an apocalyptic number.

It is an amenable number.

211112134100057 is a deficient number, since it is larger than the sum of its proper divisors (1).

211112134100057 is an equidigital number, since it uses as much as digits as its factorization.

211112134100057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1680, while the sum is 29.

Adding to 211112134100057 its reverse (750001431211112), we get a palindrome (961113565311169).

The spelling of 211112134100057 in words is "two hundred eleven trillion, one hundred twelve billion, one hundred thirty-four million, one hundred thousand, fifty-seven".